“数学之美”团员448755083为你解答!
∫∫xy(y - x)dxdy
= ∫[y∫(xy - x²)dx]dy
= ∫[y∫d(0.5yx² - x³/3)]dy
= ∫{y[(0.5y - 1/3) - (0.5y + 1/3)]}dy
=-∫(2y/3)dy
=-y²/3 |(-1,1)
= 0
“数学之美”团员448755083为你解答!
∫∫xy(y - x)dxdy
= ∫[y∫(xy - x²)dx]dy
= ∫[y∫d(0.5yx² - x³/3)]dy
= ∫{y[(0.5y - 1/3) - (0.5y + 1/3)]}dy
=-∫(2y/3)dy
=-y²/3 |(-1,1)
= 0