1、已知A,B是方程x^2+2x-5=0的两个实数根,求(A^2+2AB+2A)(B^2+2AB+2B)的值.由A,B是方程x^2+2x-5=0的两个实数根得:AB=-5,A+B=-2 A^2+2AB+2A)(B^2+2AB+2B) =AB(A+2B+2)(B+2A+2) =-5(-2+B+2)(-2+A+2) =-5AB =25 2、1/2(x+y+z)方+1/2(x-y-z)(x-y+z)-z(x+y),其中x-y=6,xy=21.要详细步骤 化简得:1/2(x+y+z)方+1/2(x-y-z)(x-y+z)-z(x+y)= 1/2[(x+y)方+2z(x+y)+z方]+1/2[(x-y)方-z方]-z(x+y)= 1/2(x+y)方+1/2(x-y)方=x方+y方 由x-y=6,xy=21得,x方+y方=(x-y)方+2xy=78 3、a^2-ab+2b^2=3 求2ab-2a^2-4b^2-7的值 2ab-2a^2-4b^2-7 =2(ab-a^2-2b^2)-7 =-2(a^2-ab+2b^2)-7 =(-2)*3-7 =-6-7=-13 4、若A=2x^2+3xy-2x-3,B=-x^2+xy+2,且3A+6B的值与x无关,求y的值 3A+6B=6x^2+9xy-6x-9-6x^2+6xy+12 =15xy-6x+3 =x(15y-6)+3 5、9x+6x^2 -3(x-2/3x^2).其中x=-2 9x+6x2; -3(x-2/3x2;) =9x+6x2;-3x+2x2; =8x2;+6x =8×(-2)2;+6×(-2) =32-12 =20 6、1/4(-4x^2+2x-8)-(1/2x-1),其中x=1/2 1/4(-4x2;+2x-8)-(1/2x-1) =-x2;+1/2x-2-1/2x+1 =-x2;-1 =-(1/2)2;-1 =-1/4-1 =-5/4 7、3x'y-[2x'y-(2xyz-x'z)-4x'z]-xyz,其中x=-2,y=-3,z=1,:3x'y-[2x'y-(2xyz-x'z)-4x'z]-xyz =3x'y-2x'y+2xyz-x'z+4x'z-xyz =x'y-xyz+3x'z =4*(-3)-2*3*1+3*4*1 =-12-6+12 =-6 8、(5a^2-3b^2)+(a^2+b^2)-(5a^2+3b^2),其中a=-1,b=1 =5a^2-3b^2+a^2+b^2-5a^2-3b^2 =a^2-5b^2 =(-1)^2-5*1^2 =1-5 =-4 9、2(a^2b+ab^2)-2(a^2 b-1)-2ab^2 -2其中a=-2,b=2 =2a^2b+2ab^2-2a^2b+2-2ab^2-2 =0 10、(X-2分之1Y-1)(X-2分之1Y+1)-(X-2分之1Y-1)的平方 其中X=1.7,Y=3.9(先化简再求值) [(X-2分之1Y)-1][(X+2分之1Y)+1]-(X-2分之1Y-1)平方 =(X+2分之1Y)平方-1-(X-2分之1Y)平方+2(X-2分之1Y)-1 =(X+2分之1Y)平方-(X-2分之1Y)平方+2(X-2分之1Y)-2 =2XY+2X-Y-2 =3.9*2.4+1.4 =10.76 化间求值:下面的你自己求吧``` 1、-9(x-2)-y(x-5) (1)化简整个式子.(2)当x=5时,求y的解.2、5(9+a)×b-5(5+b)×a (1)化简整个式子.(2)当a=5/7时,求式子的值.3、62g+62(g+b)-b (1)化简整个式子.(2)当g=5/7时,求b的解.4、3(x+y)-5(4+x)+2y (1)化简整个式子.5、(x+y)(x-y) (1)化简整个式子.6、2
已知a2-4a+2=0,b+2/b=4,且a不等于b,求(a3+a2b+ab2+b3)/{(a-b)的平方}
1个回答
相关问题
-
已知:a-b=0,求a^3-(2a^4b^3-a^2b)-ab^2-b^3+2a^3^b^4
-
已知:(a-b)((a^2+AB+b^2)/3-a^2b+ab^2=(a-b)^2,且A不等于B,求A-B
-
已知ab不等于0 且a*a+ab-2(b*b)=0,求代数式(2a-b)/(2a+b)
-
已知|4a+3|+(1/2b+a)平方=0.求5(2a+b)平方-3(3a+2b)-3(2a+2b
-
已知|2a-b-3|+(3b-2)的平方=0,求5(2a-b)-2(6a-2b+4)+(4a-3b-2)的值
-
1、已知|2a-1|+4a^2-4ab+b^2=0,求a^2(a-b)+2ab(a-b)+ab^2-b^3的值 2、已知
-
已知a的平方+2ab+b平方=0求a(a+4b)-(a+2b)(a-2b)的值
-
3a2+ab-2b2=0,求a/b-b/a-(a2+b2)/ab (a,b不等于0)
-
已知|a+b+5|+(a+2)2=0,求3a2b-[2a2b-(3ab-a2b)-4a2]-2ab的值.
-
已知4A2+B2+4A=2B-2,求[(3A-B)(3A+B)-A(A-4B)+B2]÷(-4A) 已知X²-