整个外跑过程中 角动量守恒
初状态
转动惯量:I0 = 1200 kg m^2
角速度 :ω0 = 1/10 (周/秒)
末状态
转动惯量:I = I0 + mr^2 = 1200kg m^2 + 80 * (2m)^2 = 1520 kg m^2
角速度 ω
则
Iω = I0 ω0
ω = (I0/I)ω0 = (1200/1520) * (1/10) = (3/38) (周/秒)
(大约 ≈ 1周/12.7秒)
整个外跑过程中 角动量守恒
初状态
转动惯量:I0 = 1200 kg m^2
角速度 :ω0 = 1/10 (周/秒)
末状态
转动惯量:I = I0 + mr^2 = 1200kg m^2 + 80 * (2m)^2 = 1520 kg m^2
角速度 ω
则
Iω = I0 ω0
ω = (I0/I)ω0 = (1200/1520) * (1/10) = (3/38) (周/秒)
(大约 ≈ 1周/12.7秒)