因为角BAC=角DAC,所以角DAB=角EAC,又因为AD=AE,AB=AC,所以:△ABD≌△ACE(SAS)
如图,已知在△ABC与△ADE中,AB=AC,AD=AE,且∠BAC=∠DAE,试说明:△ABD≌△ACE
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相关问题
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如图,AB=AC,AD=AE,∠BAC=∠DAE.求证:△ABD≌△ACE.
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如图,AB=AC,AD=AE,∠BAC=∠DAE.求证:△ABD≌△ACE.
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如图,已知∠BAC=∠DAE ,∠ABD=∠ACE ,BD=CE 求证:AB=AC,AD=AE
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(2012•通州区一模)如图,在△ABC和△ADE中,AB=AC,AD=AE,∠BAC=∠DAE,求证:△ABD≌△AC
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如图,已知Rt△BAC与Rt△DAE中,∠BAC=90°,∠DAE=90°,且AB=AC,AD=AE,说明理由:(1)
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已知如图,AB=AC,AD=AE,角BAC=角DAE,试说明BC=CE
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已知,如图AB=AC,AD=AE,∠BAC=∠DAE
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已知:如图,AB=AC,AD=AE,∠BAC=∠DAE,
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已知:如图,AB=AC,AD=AE,∠BAC=∠DAE,
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已知:如图,AB=AC,AD=AE,∠BAC=∠DAE,