设m+1=a n-1=b
(m+1)*(n-1)=a*b=(a+1)(b+4)-(a+2)(b+3)
=(m+1+1)(n-1+4)-(m+1+2)(n-1+3)
=(m+2)(n+3)-(m+3)(n+2)
=mn+3m+2n+6-(mn+2m+3n+6)
=m-n
当m=2005,n=2004时.原式=2005-2004=1
设m+1=a n-1=b
(m+1)*(n-1)=a*b=(a+1)(b+4)-(a+2)(b+3)
=(m+1+1)(n-1+4)-(m+1+2)(n-1+3)
=(m+2)(n+3)-(m+3)(n+2)
=mn+3m+2n+6-(mn+2m+3n+6)
=m-n
当m=2005,n=2004时.原式=2005-2004=1