Question

已知函数f(x)=ax^5+bx^3+c/x+4.若f(-2)=-2,则f(2)=?

Answer 1

f(-2)=a（-2）^5+b（-2）^3+c/（-2）+4

= -a*2^5-b*2^3-c/2+4

=-（a*2^5+b*2^3+c/2）+4

= -2

所以 a*2^5+b*2^3+c/2 = 6

f（2）=a*2^5+b*2^3+c/2 +4=6+4=10