Question

幂的运算：已知10^a=20,10^b=0.2,求：9^a/32^b

Answer 1

题目有误

9^a/32^b 应改为：9^a/3^2b

10^a=20,10^b=0.2

10^a/10^b=20/0.2

10^(a-b)=100

10^(a-b)=10^2

a-b=2

9^a/3^2b

=(3^2)^a/3^2b

=3^2a/3^2b

=3^(2a-2b)

=3^[(a-b)^2]

=3^(2^2)

=3^4

=81