(1)Q吸=cm(t-t0)
=4.2×103J/(kg•℃)×100kg×(50℃一20℃)
=1.26×107J;
答:吸收太阳的热量是1.26×107J;
(2)Q=W=Pt
t=[W/P]=
1.26×107J
2000W=6300s;
答:需要时间是6300s;
(3)电加热过程存在热损失,或实际电压低于220V.
(1)Q吸=cm(t-t0)
=4.2×103J/(kg•℃)×100kg×(50℃一20℃)
=1.26×107J;
答:吸收太阳的热量是1.26×107J;
(2)Q=W=Pt
t=[W/P]=
1.26×107J
2000W=6300s;
答:需要时间是6300s;
(3)电加热过程存在热损失,或实际电压低于220V.