6tan60°-sin45°+tan45°/(ta - 知识问答

6tan60°-sin45°+tan45°/(tan60°-2tan45°)+cos60°

1个回答

6tan60°-sin45°+tan45°/(tan60°-2tan45°)+cos60°
=6*√3-√2/2+1/(√3-2)+1/2
=6√3-√2/2+(√3+2)/(-1)+1/2
=6√3-√2/2-√3-2+1/2
=5√3-√2/2-3/2
=(10√3-√2-3)/2

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