因式分解 2a²+4ab+2b²-8

1个回答

  • 1、

    2a^2+4ab+2b^-8

    =2(a^2+2ab+b^2-4)

    =2[(a^2+2ab+b^2)-4]

    =2[(a+b)^2-2^2]

    =2*(a+b+2)*(a+b-2)

    2、

    (1/2)x^2+2xy+2y^4

    ——后面是y^4吗?!个人觉得应该是y^2!

    3、

    x^2-y^2+2y-1

    =x^2-(y^2-2y+1)

    =x^2-(y-1)^2

    =(x+y-1)*(x-y+1)