移向得到,
An=An+1-An+2
=An+2-An+3-An+2=-An+3
即An=-An+3
∴有An+3=-An+6
∴An=An+6
由于2008=6×334+4
∴A2008=A4=-A1=-3
数列{an}满足a1=3,a2=6,an+2=an+1-an,求a2008
2个回答
相关问题
-
数列{an}满足a1=3,a2=6,an+2=an+1-an,求a2013
-
数列an满足a1=2 an+1=an/an+3 求an
-
数列[An]满足a1=2,a（n+1）=3an-2 求an
-
一道很难的数列题!数列{an}中,a1=1,a2=6,an+2=an+1-an,求a2008
-
数列an满足a1=2,an+1=an²求an
-
数列{an}满足a1=1,a2=2,an=1/2(an-1+an-2)(n=3,4...),数列{bn}满足bn=an+
-
已知数列{an}满足an+1=2an+3.5^n,a1=6.求an
-
若数列an满足a1=1.a2=2,an=an-1/an-2,求a2004
-
数列{an}满足lg(1+a1+a2+a3.+an)=n+1求an
-
已知数列an满足:a1=1,a2=6,an+2=-an