题目应该是求(1+1/2+1/3+……+1/100)*(1/2+1/3+……+1/101)-(1+1/2+1/3+……+1/101)*(1/2+1/3+……+1/100)的值
设1+1/2+1/3+……+1/100=A,1/2+1/3+……+1/101=B
所以B-A=1/101-1
因为1+1/2+1/3+……+1/101=1/2+1/3+……+1/101+1=B+1
1/2+1/3+……+1/100=1+1/2+1/3+……+1/100-1=A-1
所以原式=AB-(A-1)(B+1)
=AB-AB-A+B+1
=B-A+1
=1/101+1
=1/101