分解因式:x的立方(y-z)+y的立方(z-x)+z的立方( x-y)

1个回答

  • x的立方(y-z)+y的立方(z-x)+z的立方( x-y)

    =x³y-x³z+y³z-xy³+xz³-yz³

    =(x³y-xy³)-(x³z-y³z)+(xz³-yz³)

    =xy(x²-y²)-z(x³-y³)+z³(x-y)

    =xy(x+y)(x-y)-z(x-y)(x²+xy+y²)+z³(x-y)

    =(x-y)(x²y+xy²-x²z-xyz-y²z+z³)

    =(x-y)[(x²y-x²z)+(xy²-xyz)-(y²z-z³)]

    =(x-y)[x²(y-z)+xy(y-z)-z(y+z)(y-z)]

    =(x-y)(y-z)(x²+xy-yz-z²)

    =(x-y)(y-z)[(x²-z²)+(xy-yz)]

    =(x-y)(y-z)[(x+z)(x-z)+y(x-z)]

    =(x-y)(y-z)(x-z)(x+y+z)