Question

求反函数!要过程! y=2sin3x,x属于[－π/6,π/6]

Answer 1

y=2sin3x

sin3x=y/2

3x=arcsin(y/2)

x=arcsin(y/2) /3

当x=－π/6时 y=2sin(－3π/6)=-2sinπ/2=-2

当x=π/6时 y=2sin(π3/6)=2sinπ/2=2

∴反函数是

y=arcsin(x/2) /3 x∈[-2,2]