Question

若关于x的方程（x-5）/（x-6）-（x-6）/（x-5）=k/（xˆ2-11x+30）,求k 的取值范围

Answer 1

(x-5)/(x-6)-(x-6)/(x-5)=k/(x²-11x+30)

[(x-5)²-(x-6)²]/(x-6)(x-5)=k/(x²-11x+30)

(2x-11)/(x-6)(x-5)=k/(x-6)(x-5）

2x-11=k (x-6)(x-5)≠0

x=(k+11)/2 x≠5且x≠6

(k+11)/2≠5且(k+11)/2≠6

k≠±1