(sina)^2+(cosa)^2=1
所以(sina)^2+4(sina)^2=1
(sina)^2=1/5
3sin2a=6sinacosa=-12(sina)^2=-12/5
-4cos2a=-4[1-2(sina)^2]=-4+8(sina)^2=-12/5
命题得证
(sina)^2+(cosa)^2=1
所以(sina)^2+4(sina)^2=1
(sina)^2=1/5
3sin2a=6sinacosa=-12(sina)^2=-12/5
-4cos2a=-4[1-2(sina)^2]=-4+8(sina)^2=-12/5
命题得证