Question

化学动态35#%……多多回答哦,

Answer 1

1.

2Fe+3H2SO4=Fe2(SO4)3+3H2

5.6 14.7 60 0.3

硫酸过量..恰好完全反应,则C含量==(8.7-5.6)/8.7==24%

...有点大了,题没问题吧!那就是生铁了

2.

溶质质量分数==60/(105.9-14.7)=66%