Question

根号下X-1的导数如何求解?需要注明步骤,

Answer 1

y=√（x-1）=(x-1)^(1/2)

y'=[(x-1)^(1/2)]'*(x-1)'

=(1/2)*(x-1)^(1/2-1)*1

=(1/2)/√(x-1)