Question

3分之1（-3ax²-ax+3)-(-ax²-2分之1ax-1),其中a=-2,x=3.

Answer 1

3分之1（-3ax²-ax+3)-(-ax²-2分之1ax-1)

=1/3*(-3ax²-ax+3)+ax²+1/2*ax+1

=-ax^2-1/3*ax+1+ax^2+1/2*ax+1

=1/6*ax+2

=1/6*(-2)*3+2

=-1+2

=1