我想知道为什么 log(2^2) 3=1/2*lo

我想知道为什么 log(2^2) 3=1/2*log2 3 log8 3=log(2^3) 3=1/3*log2 3

1个回答

(log3 4+log3 8)(log2 3+log2 9)+(log3 根号2)(log9 7)/(log1/3 7)
NO.1 (log3 2 + log9 2) (log4 3 + log8 3)
1.log3 3/log27 64 2.log8 9 log3 2
对数计算1.{log(4)（3）+ log(8) (3)} X {log(3)(2)+log(9)(2)}2.{log(
为什么log1/3 2= - log3 2
(log4 3+log8 3)*(log3 2+log4 2)
log(√2+1)(3+2√2)+log√3（√6+3√3）-log3(2+√3)=
求值.(log3^2+log9^3)*(log4^3+log8^3)+(log3^3^1/2)^2+ln根号下e-lg1
计算：（log4 9+log8 3)(log3 2+log9 2)-log1/3 4√81
已知log2[log1/2(log2x)]=log3[log1/3(log3y)]=log5[log1/5(log5z)