Question

直角三角形角BAC=90度,AD垂直BC,CE平分角BCA,交AB于点E,那么AE等于AF吗?为什么

Answer 1

AE等于AF

证明∠AEF=∠AFE就可以了

∠ACE=∠BCE

∠DAC=∠CBA

∠AEF=∠ABC+∠BCE

∠AFE=∠ACE+∠CAF

∠AEF=∠AFE

所以AE等于AF