Question

f（x）=sin（2^x-2^x\1)的导数

Answer 1

f（x）=sin[2^x-2^(1/x)]

f'(x)=cos[2^x-2^(1/x)]* [2^x-2^(1/x)]'

=[2^x*ln2-2^(1/x)*ln2*(1/x)']*cos[2^x-2^(1/x)]

=[2^x+1/x²*2^(1/x)]ln2*cos[2^x-2^(1/x)]