很遗憾,我毕业已经4年多了,你自己加油吧,不好意思了.
如题.1 ∫cos²x-sin²x/cos²xsin²x dx 2 ∫1+cos
1个回答
相关问题
-
∫xsin2xdx=1/2∫x(-cos2x)′dx=1/2(-xcos2x+∫(x)′cos2xdx)=-x/2cos
-
求证(cos^2x-sin^2x)(cos^4x+sin^4x)+1/4sin2xsin4x=cos2x
-
求不定积分:$(sin x +cos x)/(1+cos^2x) dx
-
大一微积分求解①∫cos²xsin²xdx②∫cot²x+cos²(x/2)dx
-
化简f(x)=sin^2(x)+xsin(x)cos(x)+3cos^2(x)
-
(1+cos x-sin x)/(1-sin x-cos x)+(1-cos x-sin x)/(1-sin x+cos
-
∫ 1/((4(cos x)^2)-((sin x)^2)) dx
-
几道微积分题∫xsin(x^2)cos3(x^2)dx∫(cscx)^5dx
-
求解∫1/(cos^4(x)sin^2(x))dx
-
∫ (1+cos^2 x)/cos^2 x dx =