Question

计算:（3x^2）^3-7x^3【x^3-x（4x^2+1）】-（-x^2）^2

Answer 1

(3x^2)^3-7x^3[x^3-x(4x^2+1]+(-x^2)^2

=27x^6-7x^3[x^3-4x^3-x]+x^4

=27x^6+21x^6+7x^4+x^4

=48x^6+8x^4

=48/64+1/2

=3/4+1/2

=5/4

你做的是对的!