a3=2S2+1,(1)
a4=2S3+1,(2)
(2)-(1),a4-a3=2(S3-S2)=2a3
a4=3a3,q=3
M=a1(1-q^n)/(1-q)
数列{2/an}的公比是1/q,首项是2/a1
N=(2/a1)(1-1/q^n)/(1-1/q)=(2/a1)q^(n-1)*[(1-q^n)/(1-q)]
M/N=a1/[(2/a1)q^(n-1)]=1/2*(a1^2)*q^(n-1)
a3=2S2+1,(1)
a4=2S3+1,(2)
(2)-(1),a4-a3=2(S3-S2)=2a3
a4=3a3,q=3
M=a1(1-q^n)/(1-q)
数列{2/an}的公比是1/q,首项是2/a1
N=(2/a1)(1-1/q^n)/(1-1/q)=(2/a1)q^(n-1)*[(1-q^n)/(1-q)]
M/N=a1/[(2/a1)q^(n-1)]=1/2*(a1^2)*q^(n-1)