Question

y=2x+1/2x-1求反函数2的X次方 求反函数

Answer 1

x=(2^y+1)/(2^y-1)

x*2^y-x=2^y+1

(x-1)2^y=x+1

2^y=(x+1)/(x-1)

y=log2[(x+1)/(x-1)]