1:
Δ=0得,4m^2-4(n-1)=0 ==> m^2=n-1>0
故开口方向为上
2:
Δ=4(n-1)^2+4m^2>0
故命题得证
3:
由题,该三角形面积为底边AB,高为h(即为C点的纵坐标)
AB=|X1-X2|
h=|y(0)|=1
S=1/2·AB·h得
AB=4
4(n-1)^2+4m^2=(4m^2)^2
又由1得m^2=n-1
得m^2=n-1=1/3
故
解析式:y=(1/3)x^2+2/3x-1
1:
Δ=0得,4m^2-4(n-1)=0 ==> m^2=n-1>0
故开口方向为上
2:
Δ=4(n-1)^2+4m^2>0
故命题得证
3:
由题,该三角形面积为底边AB,高为h(即为C点的纵坐标)
AB=|X1-X2|
h=|y(0)|=1
S=1/2·AB·h得
AB=4
4(n-1)^2+4m^2=(4m^2)^2
又由1得m^2=n-1
得m^2=n-1=1/3
故
解析式:y=(1/3)x^2+2/3x-1