1/(2X3)+1/(3X4)+1/(4X5)+1/(5X6)+...+1/(100X101)=?
2个回答
=(1/2-1/3)+(1/3-1/4)+……+(1/100-1/101)
中间正负抵消
=1/2-1/101
=99/202
相关问题
1x1-2x2+3x3-4x4+5x5-6x6.-100x100+101x101
1 1 1 1 1 ——+——+——+——+```````` —— 2X3 3X4 4X5 5X6 99X100
下面的等式成立:x1x2=x2x3=x3x4=x4x5=''''=x100x101=x101x1=1.求x1,x2,""
1x3+2x4+3x5+4x6..+99x101=?
有趣的数学题1.1x2x3 + 2x3x4 + 3x4x5 +.+100x101x102 2.1/(1x2x3) + 1
1/2X1/3+1/3X1/4+1/4X1/5+1/5X1/6+.+1/99X1/100=?
1/2X3X4X5+1/3X4X5X6+1/4X5X6X7.1/97X98X99X100=?
4/5x+2=-1/3x-1.-5/6x+2=-1/3x-1.6(x-4)=-3(4+2x).
6(x+1)=4(x+4) 6(x-1)=4(3-2x) 5-3x=8-4x 5-(x+3)=4-3x 1/2(x+6)
1/1X2+1/3X4+1/5X6+……+1/99X100=?