x^2+2x-3/x^3+7x^2+7x-15
2个回答
因为:x^2+2x-3=(x+3)(x-1)
x^3+7x^2+7x-15=(x+5)(x+3)(x-1)
所以:原式=(x+3)(x-1)/(x+5)(x+3)(x-1)
=1/(x+5)
相关问题
2x^2+3x+1=0 2x^2-7x-15=0 3x^2-7x-6=0
3(X-7)+2(X-4)=15怎么解 3(X-7)+2(X-4)=15怎么解
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2X+15+2X+3X=7X+15=50怎么解?
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(x+2)^3-(x+2)-(7^3-1) =(x+2-7)[(x+2)^2+7(x+2)+49]-(x+2-7)中^是