帮我解几道数学题1、如果(x-2)(x^2+ax+b)的乘积中不含x^2项和x项,则a、b的值分别是( )A.a=4,b

1个回答

  • 含x^2与x项的系数之和分别为:a-2,b-2a

    a-2=0 a=2

    b-2a=0 b=2a=4

    2.4x^2+20xy+25y^2=0

    (2x+5y)^2=0

    2x+5y=0

    x=-3

    -6+5y=0 y=6/5

    (2x-5y)^2=(-6-6)^2=144

    3.

    4x^2+1+kx是关于x的完全平方式

    4x^2+1+kx=(2x±1)^2=4x^2+1±4x k=±4

    4.[(x^2+x)/x]-2x=x+1-2x=1-x

    5.1/4a^2+ab+b^2=(b+1/2a)^2

    周长:4*(b+1/2a)^2

    6.a-b=b-c=3/5 a-c=6/5

    (a-b)^2+(a-c)^2+(b-c)^2=2(a^2+b^2+c^2)-2(ab+ac+cb)=54/25

    ab+ac+cb=[2-54/25]/2=-2/25

    7.1/2x^2+2xy+2y^2=(√2/2x+√2y)^2

    8.a^2+b^2+4a-6b+13=0

    (a+2)^2+(b-3)^2=0

    a+2=0 a=-2

    b-3=0 b=3

    a^2+b^3=4+27=31

    9.1.5×10^6*3.0×10^5/(1.5×10^5)^2=20