Question

解方程组x-y-3z=4 3x+y-z=6 -x+3y+z=8 能把详细的过程告诉我吗?x、y、z分别是几?谢谢

Answer 1

x-y-3z=4 (1)

3x+y-z=6 (2)

-x+3y+z=8 (3)

(1)+(2)

4x-4z=10(4)

(1)×3+(3)

2x-8z=12+8=20

x-4z=10 (5)

(4)-(5)

3x=0

x=0

z=(x-10)/4=-5/2

y=x-3z-4=7/2