Question

1.若x,y为有理数,且|x-1|+(y-2)^2=0.求-x^2+(-y^2)+x^y的值.

Answer 1

1.|x-1|=0 (y-2)^2=0

X=1 Y=2 -x^2+(-y^2)+x^y=-1-4+1=-4

2.m为偶数,n为奇数,mn为偶数,(-1)^m=1 (-1)^n=-1 (-1)^mn=1

（-1）＾m+（-1）＾n+（-1）＾mn

=1-1+1

=1

3.有多种情况`````