1/x(x+1)+1/（x+1)（x+2)+...+1/(x+2012)(x+2013)
= 1/x - 1/(x+1) + 1/(x+1) - 1/(x+2) +……+ 1/(x+2012) - 1/(x+2013)
= 1/x - 1/(x+2013)
=1 - 1/2014
= 2013/2014
化简1/1*2+1/2*3+1/3*4+.1/n(n+1)
2个回答
相关问题
-
定义n!=1*2*3*.*(n-1)*n,例如4!=1*2*3*4,化简1/2!+2/3!+n/(n+1)!
-
化简1/（2!）+2/（3!）+3/（4!）……(n-1)/(n!)
-
阶乘化简1／2!+2/3!+3/4!+...+n/(n+1)!化简.
-
化简1/2!+2/3!+3/4!+.+(n-1)/n!n∈n*,n≥2
-
化简：1*1!+2*2!+3*3!+.+n*n!
-
设n∈N+,且n>2,化简：3/(1!+2!+3!)+4/(2!+3!+4!)+...+(n+2)\n!+(n+1)!+
-
3(n-1)²-2(n-1)+1怎么化简
-
化简：（n+1）（n+2）分之1+（n+2）（n+3）分之1+（n+3）（n+4）分之1
-
化简{[2*1d+3*2d+4*3d+……+n(n-1)d]+n(n-1)/2*d*a}/[(n-1)n*d/2]
-
化简函数f(x)=1+1+2+1+2+3+1+2+3+4+1+2+……+n