1/x(x+3)+1/(x+3)(x+6)+1/(x+6)(x+9)
=1/3[3/x(x+3)+3/(x+3)(x+6)+3/(x+6)(x+9)]
=1/3[1/x-1/(x+3)+1/(x+3）-1/(x+6)+1/(x+6）-1/(x+9)]
=1/3[1/x-1/(x+9)]
=1/3*(x+9-x)/x(x+9)
=1/3*9/x(x+9)
=3/x(x+9)
计算1/x(x+3)+1/(x+3)(x+6)+1/(x+6)(x+9)
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