化简[1-sin(π+2α)+cos（2α-7π)

化简[1-sin(π+2α)+cos（2α-7π)]/[1+cos(π-2α)+sin(2α+6π)]

2个回答

[1-sin(π+2α)+cos（2α-7π)]/[1+cos(π-2α)+sin(2α+6π)]
=[1+sin2α-cos2a]/[1-cos2α+sin2α]
=1
奇变偶不变,符号看象限

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