答:3/(x^2+2x)-1/(x^2-2x)=0
3(x-2)/[x(x+2)(x-2)]-(x+2)/[x(x-2)(x+2)]=0
所以:(3x-6-x-2)/[x(x+2)(x-2)]=0
3x-6-x-2=0
2x-8=0
x=4
经检验x=4是原分式方程的根
答:3/(x^2+2x)-1/(x^2-2x)=0
3(x-2)/[x(x+2)(x-2)]-(x+2)/[x(x-2)(x+2)]=0
所以:(3x-6-x-2)/[x(x+2)(x-2)]=0
3x-6-x-2=0
2x-8=0
x=4
经检验x=4是原分式方程的根