6x平方 - x - 12 = 0
求根公式：x = { 1 ± √(1^2+4*6*12) } / (2*6) = (1±√289)/12
x1 = (1-√289)/12
x2 = (1+√289)/12
6x平方 - 6x - 12 = 0
6(x+1)(x-2) = 0
x1=-1,x2=2
6x平方 - x - 12 = 0
求根公式：x = { 1 ± √(1^2+4*6*12) } / (2*6) = (1±√289)/12
x1 = (1-√289)/12
x2 = (1+√289)/12
6x平方 - 6x - 12 = 0
6(x+1)(x-2) = 0
x1=-1,x2=2