Question

解二元一次方程组\不等式组~{ 3(x-1)=y+5 5(y-1)=3(x+5){ 1/2x+1/25(x-1) 4/3

Answer 1

3(x-1)=y+5得3x=y+2代入5(y-1)=3(x+5)=3x+15

得5y-5=y+17得y=11/2,x=5/2

1/2x+1/2