Question

解方程(2x²+3x-1）（2x²-5x+4)=(x²-1)(4x²+1)

Answer 1

(2x²+3x-1）（2x²-5x+4)=(x²-1)(4x²+1)

4x^4-10x³+8x²+6x³-15x²+12x-2x²+5x-4=4x^4+x²-4x²-1

-4x³-9x²+17x-4=-3x²-1

4x³+6x²-17x+3=0

4x³+12x²-(6x²+17x-3)=0

4x²(x+3)-(x+3)(6x-1)=0

(x+3)(4x²-6x+1)=0

x+3=0,或4x²-6x+1=0

x1=-3,x2,x3=(3±√5)/4