我来试试
1.原式=∫1/(2+5x)dx-2∫x/(2+5x)dx=1/5*∫d(5x+2)/(5x+2)-2/5*∫(5x+2-2)/(5x+2)dx=1/5*∫d(5x+2)/(5x+2)-2/5∫dx+4/25∫d(5x+2)/(5x+2)=9/25*ln(5x+2)-2/5x+C
有字数限制其他的问题你hi我
我来试试
1.原式=∫1/(2+5x)dx-2∫x/(2+5x)dx=1/5*∫d(5x+2)/(5x+2)-2/5*∫(5x+2-2)/(5x+2)dx=1/5*∫d(5x+2)/(5x+2)-2/5∫dx+4/25∫d(5x+2)/(5x+2)=9/25*ln(5x+2)-2/5x+C
有字数限制其他的问题你hi我