设x=2012.5
根号下的式子为=(x-3/2)(x-1/2)(x+1/2)(x+3/2)+1
=(x^2-9/4)(x^2-1/4)+1
=x^4-5/2x^2+25/16
=(x^2-5/4)^2
开根号=x^2-5/4
如有意见,欢迎讨论,共同学习;如有帮助,
设x=2012.5
根号下的式子为=(x-3/2)(x-1/2)(x+1/2)(x+3/2)+1
=(x^2-9/4)(x^2-1/4)+1
=x^4-5/2x^2+25/16
=(x^2-5/4)^2
开根号=x^2-5/4
如有意见,欢迎讨论,共同学习;如有帮助,