由x2+y2+8x+6y+25=0得（x+4）2+（y+3）2=0，
解得：x=-4，y=-3，
∴原式=
(x+2y)(x−2y)
(x+2y)2−
x
x+2y=[−2y/x+2y]=
−2×(−3)
−4+2×(−3)=-[3/5]．
已知x2+y2+8x+6y+25=0，求x2−4y2x2+4xy+4y2−xx+2y的值．
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