Question

室温下,将2g苯(C6H6)完全燃烧生成液态水和CO2,放出83.6kJ的热量,写出C6H6燃烧热的

Answer 1

C6H6(l)+(15/2)O2(g)=6CO2(g)+3H2O(l) △H=-3260.4kj/mol

H2O(g)=H2O(l) △H=-43.92kj/mol

(1/3)C6H6(l)+(5/2)O2(g)=2CO2(g)+H2O(g) △H=-1042.88kj/mol