(1)2003²-2002*2004=2003²-(2003-1)(2003+1)=2003²-(2003²-1)=1
(2)(x+y+2)(x-y-2)=[x+(y+2)][x-(y+2)]=x²-(y+2)²
(3)(x-2y+z)(x+2y-z)=[x+(-2y+z)][x-(-2y+z)]=x²-(z-2y)²
(4)3(2y+1)(1-2y)-4(-3y-2)(3y-2) =3(1-4y²)-4(4-9y²)=24y²-13
(1)2003²-2002*2004=2003²-(2003-1)(2003+1)=2003²-(2003²-1)=1
(2)(x+y+2)(x-y-2)=[x+(y+2)][x-(y+2)]=x²-(y+2)²
(3)(x-2y+z)(x+2y-z)=[x+(-2y+z)][x-(-2y+z)]=x²-(z-2y)²
(4)3(2y+1)(1-2y)-4(-3y-2)(3y-2) =3(1-4y²)-4(4-9y²)=24y²-13