Question

计算[(a^2-4b^2)/(a^2+4ab+4b^2)]÷[(a^2+ab-6b^2)/(a^2+5ab+6b^2)]

Answer 1

[(a^2-4b^2)/(a^2+4ab+4b^2)]÷[(a^2+ab-6b^2)/(a^2+5ab+6b^2)]

=(a+2b)(a-2b)/(a+2b)^2÷(a+3)(a-2)/(a+2)(a+3)

=(a-2b)/(a+2b)÷(a-2b)/(a+2b)

=1