Question

关于溶液浓度的1.在浓度为3.6×10^-6 mol/L 的HCLO4溶液中,氢氧根离子(OH-)的浓度为多少?2.浓度

Answer 1

【1】HClO4是强酸,完全电离.

c(H+) = c(HClO4) = 3.6*10^-6 mol/L

则,c(OH-) = 10^-14 / c(H+) = 2.78*10^-9mol/L

【2】H2SO4二元强酸,完全电离.

c(H+) = 2c(H2SO4) = 2* 2.00*10^-1 =4.00*10^-1mol/L

PH=-logc(H+) = - log(4.00*10^-1) = 1-0.6 = 0.4