设x+1=a
公式=(a-1)(a+a^2+……+a^2013)=(a-1)[(1-a^2014)/(1-a)]=x[(x+1)^2014/x]=(x+1)^2014
化简1+x+x（x+1）+x（x+1）^2+x（x+1）^3+…+x（x+1）^2013
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