Question

“已知（2x-1）＾2=ax^2+bx+c,求a+c,4a+b+4c的值.”

Answer 1

(2x-1)^2去括号为4x^2-4X+1

因（2x-1）＾2=ax^2+bx+c

故 4x^2-4X+1=ax^2+bx+c

那么a=4,b=-4,c=1

a+c=5

4a+b+4c=16