Question

(m平方-1)分之(m平方-4m+4)除以(m-1)分之(m-2)+(m-1)分之2

Answer 1

(m²-1)分之(m²-4m+4)÷(m-1)分之(m-2)+(m-1)分之2

=[(m+1)(m-1)]分之(m-2)²×(m-2)分之(m-1)+(m-1)分之2

=(m+1)分之(m-2)+(m-1)分之2

=[(m+1)(m-1)]分之[(m-2)(m-1)]+[(m+1)(m-1)]分之[2(m+1)]

=[(m+1)(m-1)]分之[(m-2)(m-1)+2(m+1)]

=[(m+1)(m-1)]分之(m²-3m+2+2m+1)

=(m²-1)分之(m²+m+3)