Question

已知幂函数满足：x≥4,则f(x)=（1/2)^x;当x＜4时,f(x)=f(x+1),则f(2+l以2为底3的对数）为

Answer 1

由于2+log234,则f(3+log23)=（1/2)^(3+log23)

=(1/8)*(1/2)^(log23)

=(1/8)*2^(-log23)

=(1/8)*2^[log2(1/3)]=(1/8)(1/3)=1/24